2x-0.01x^2=2

Solution for 2x-0.01x^2=2 equation:

2x-0.01x^2=2

We move all terms to the left:

2x-0.01x^2-(2)=0

a = -0.01; b = 2; c = -2;
Δ = b2-4ac
Δ = 22-4·(-0.01)·(-2)
Δ = 3.92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{3.92}}{2*-0.01}=\frac{-2-\sqrt{3.92}}{-0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{3.92}}{2*-0.01}=\frac{-2+\sqrt{3.92}}{-0.02}
$